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hahajamiexlyn · Aug 22, 2007, 06:58 AM

Okay I figured out all of the problems in my packet except

-4(2x-1/2x+1)^-3[2(2x+1)-2(2x-1)/(2x+1)^2]

:eek:

ebaines · Aug 22, 2007, 07:14 AM

Please clarify - is this the expression you're trying to simplify?

$<br /> -4 \left( \frac {2x-1} {2x+1} \right) ^ {-3} \left{ 2(2x+1) - 2 \frac {(2x-1)} {(2x+1)^2} \right}<br />$

hahajamiexlyn · Aug 23, 2007, 06:30 AM

Originally Posted by ebaines

Please clarify - is this the expression you're trying to simplify?

$<br /> -4 \left( \frac {2x-1} {2x+1} \right) ^ {-3} \left{ 2(2x+1) - 2 \frac {(2x-1)} {(2x+1)^2} \right}<br />$

no it's

ebaines · Aug 23, 2007, 02:29 PM

In your original post you showed the first term as (2x-1/2x+1)^-3, but in the repost you have it as (2x+1)^3/(2x-1) -- please confirm that the repost is correct. Given that the subject title is about negative exponents, I'm wondering if a typo or two didn't creep into the repost?

Assuming the repost is correct, I would suggest first combining the stuff in the numerator inside the brackets: 2(2X+1)-2(2x-1). Multiply through and this becomes simply 4. Then look at the (2x+1) terms in the denominators - you have (2X+1)(2x+1)^2 -- this is the same as (2x+1)^3. Do you see that? Can you take it from there?