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-   -   Simplifying Negatives part 2 (https://www.askmehelpdesk.com/showthread.php?t=121833)

  • Aug 22, 2007, 06:58 AM
    hahajamiexlyn
    Simplifying Negatives part 2
    Okay I figured out all of the problems in my packet except


    -4(2x-1/2x+1)^-3[2(2x+1)-2(2x-1)/(2x+1)^2]

    :eek:
  • Aug 22, 2007, 07:14 AM
    ebaines
    Please clarify - is this the expression you're trying to simplify?

  • Aug 23, 2007, 06:30 AM
    hahajamiexlyn
    Quote:

    Originally Posted by ebaines
    Please clarify - is this the expression you're trying to simplify?


    no it's
    http://i14.tinypic.com/6byd541.jpg
  • Aug 23, 2007, 02:29 PM
    ebaines
    In your original post you showed the first term as (2x-1/2x+1)^-3, but in the repost you have it as (2x+1)^3/(2x-1) -- please confirm that the repost is correct. Given that the subject title is about negative exponents, I'm wondering if a typo or two didn't creep into the repost?

    Assuming the repost is correct, I would suggest first combining the stuff in the numerator inside the brackets: 2(2X+1)-2(2x-1). Multiply through and this becomes simply 4. Then look at the (2x+1) terms in the denominators - you have (2X+1)(2x+1)^2 -- this is the same as (2x+1)^3. Do you see that? Can you take it from there?

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