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    jordo6889's Avatar
    jordo6889 Posts: 13, Reputation: 1
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    #1

    Oct 26, 2009, 09:53 AM
    find focus of parabola by a given equation
    Find the focus of the parabola given by the equation -x^2-8x-4y-16=0
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    jordo6889 Posts: 13, Reputation: 1
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    #2

    Oct 26, 2009, 09:57 AM
    Parabloid vertex
    The antenna of a radio telescope is a parabloid measuring 54 feet across with a depth of 30 feet. Determine, to the nearest tenth of a foot, the distance from the vertex to the focus of this antenna.
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    galactus Posts: 2,271, Reputation: 282
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    #3

    Oct 26, 2009, 10:04 AM
    Quote Originally Posted by jordo6889 View Post
    The antenna of a radio telescope is a parabloid measuring 54 feet across with a depth of 30 feet. Determine, to the nearest tenth of a foot, the distance from the vertex to the focus of this antenna.

    Sketch the parabola on the xy-plane with the vertex at the origin and its axis along the x-axis. An equation of the parabola is

    Since the diameter is 54, its radius is 27. Therefore, a point on the parabola is (30,27).



    solve for p, the distance from the vertex to the focus.
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