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-   -   Find focus of parabola by a given equation (https://www.askmehelpdesk.com/showthread.php?t=409789)

  • Oct 26, 2009, 09:53 AM
    jordo6889
    find focus of parabola by a given equation
    Find the focus of the parabola given by the equation -x^2-8x-4y-16=0
  • Oct 26, 2009, 09:57 AM
    jordo6889
    Parabloid vertex
    The antenna of a radio telescope is a parabloid measuring 54 feet across with a depth of 30 feet. Determine, to the nearest tenth of a foot, the distance from the vertex to the focus of this antenna.
  • Oct 26, 2009, 10:04 AM
    galactus
    Quote:

    Originally Posted by jordo6889 View Post
    The antenna of a radio telescope is a parabloid measuring 54 feet across with a depth of 30 feet. Determine, to the nearest tenth of a foot, the distance from the vertex to the focus of this antenna.


    Sketch the parabola on the xy-plane with the vertex at the origin and its axis along the x-axis. An equation of the parabola is

    Since the diameter is 54, its radius is 27. Therefore, a point on the parabola is (30,27).



    solve for p, the distance from the vertex to the focus.

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