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    Despick's Avatar
    Despick Posts: 5, Reputation: 1
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    #1

    Mar 26, 2013, 06:30 AM
    Word problem please help
    opening night of a theater sold a total of 1,000 tickets. The front row area cost $80 a seat, the back row area cost $60 a seat, and the balcony area cost $50 a seat. Total revenue from tickets was 62,800. The combined total for thee front and back seats was equal to the number of balcony seats sold. Find the number of tickets sold for each area.

    A. Begin by identifying your variables:
    X=
    Y=
    Z=

    B. set up your first equation showing the number of tickets totaling 1,000.
    C. Set up your second equation the prices of tickets totaling $62,800 in revenue.
    D. Set up your third equation showing the combined number of tickets sold for the front and back row seats were equal to the number of balcony tickets sold
    E. now use the substitution or addition method to solve for the total number of tickets sold in the respective areas of the theater. Explain the answer in words ( using units) as well.
    Cat1864's Avatar
    Cat1864 Posts: 8,007, Reputation: 3687
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    #2

    Mar 26, 2013, 08:24 AM
    Can you show us what you have tried or explain what you are having difficulty with understanding?
    fredg's Avatar
    fredg Posts: 4,926, Reputation: 674
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    #3

    Mar 26, 2013, 08:31 AM
    I will start you off with some equations:
    X = number of front row seats.
    Y = number of back row seats.
    Z = number of balcony seats.
    X + Y + Z = 1000
    80X + 60Y + 50Z = 62800
    X + Y = Z

    Now, you have to solve for x, y and z. Good luck.
    Despick's Avatar
    Despick Posts: 5, Reputation: 1
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    #4

    Mar 26, 2013, 11:51 AM
    Quote Originally Posted by fredg View Post
    I will start you off with some equations:
    X = number of front row seats.
    Y = number of back row seats.
    Z = number of balcony seats.
    X + Y + Z = 1000
    80X + 60Y + 50Z = 62800
    X + Y = Z

    Now, you have to solve for x, y and z. Good luck.

    I come up with

    X=112*80=8960 front seats
    Y=374*60=22440 back seats
    Z=62800/2=31400/50=628 balcony seats

    The math works out right but I'm not sure about how To find using the substitution or addition method.
    Despick's Avatar
    Despick Posts: 5, Reputation: 1
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    #5

    Mar 26, 2013, 11:55 AM
    [QUOTE=Despick;3428356]I come up with

    X=8960/80=112 front seats
    Y=22440/60=374 back seats
    Z=62800/2=31400/50=628 balcony seats
    Despick's Avatar
    Despick Posts: 5, Reputation: 1
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    #6

    Mar 26, 2013, 11:57 AM
    [QUOTE=Despick;3428363]
    Quote Originally Posted by Despick View Post
    I come up with

    X=8960/80=112 front seats
    Y=22440/60=374 back seats
    Z=62800/2=31400/50=628 balcony seats

    Second answer is what I come up with can you please explain

    Thank you Doug
    Despick's Avatar
    Despick Posts: 5, Reputation: 1
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    #7

    Mar 26, 2013, 12:07 PM
    Word problem 2 please help
    A company manufacturing pencils has a fixed cost of $3000 to buy machine. It costs $0.10 to produce each pencil. Each pencil sells for $0.70.

    A. Write the cost function C(x)

    B. write the revenue function R(x)

    C. Find the break even point and describe what this means
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