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    jalpalpixie's Avatar
    jalpalpixie Posts: 1, Reputation: 1
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    #1

    Apr 4, 2012, 03:55 PM
    2sec^2x-2sec^2xsin^2x-sin^2x-cos^2x=1
    2sec^2x-2sec^2xsin^2x-sin^2x-cos^2x=1
    Help??
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Apr 4, 2012, 06:58 PM
    First convert secant functions to cosine equivalents.

    Next - divide the 2/cos^2x term out of the first two terms.

    Lastly - remember the identity cos^2x + sin^2x = 1, and its variant 1-sin^2x + cos^2x.

    Post back and show us your work if you're still having difficulty.
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