Ask Me Help Desk

Ask Me Help Desk (https://www.askmehelpdesk.com/forum.php)
-   Math & Sciences (https://www.askmehelpdesk.com/forumdisplay.php?f=402)
-   -   2sec^2x-2sec^2xsin^2x-sin^2x-cos^2x=1 (https://www.askmehelpdesk.com/showthread.php?t=648469)

  • Apr 4, 2012, 03:55 PM
    jalpalpixie
    2sec^2x-2sec^2xsin^2x-sin^2x-cos^2x=1
    2sec^2x-2sec^2xsin^2x-sin^2x-cos^2x=1
    Help??
  • Apr 4, 2012, 06:58 PM
    ebaines
    First convert secant functions to cosine equivalents.

    Next - divide the 2/cos^2x term out of the first two terms.

    Lastly - remember the identity cos^2x + sin^2x = 1, and its variant 1-sin^2x + cos^2x.

    Post back and show us your work if you're still having difficulty.

  • All times are GMT -7. The time now is 12:59 PM.