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    albear's Avatar
    albear Posts: 1,594, Reputation: 222
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    #1

    Jun 7, 2007, 11:39 AM
    PA01 Jan 06 paper
    lander=1.2*10^12
    muon mass=207*9.11*10^-31
    muon speed=3*10^6
    neutral pion mass=134.972

    calculate the speed necessary for a (neutral pion) to have the same de Broglie wavelength as that of the muon (lander)

    the mark scheme uses the conservation of momentum, MV(of pion)=MV(of muon)

    yet it ends up with (3*10^6)/1.28 (1.28 is the ratio (rest mass pion)/(rest mass muon))

    I don't understand how it gets this please help quick
    albear's Avatar
    albear Posts: 1,594, Reputation: 222
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    #2

    Jun 7, 2007, 12:14 PM
    Please any help would be greatly appreciated
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #3

    Jun 7, 2007, 12:33 PM
    1. It's lambda not lander

    2. i believe it's using (De Broglie Hypothesis) and NOT the conversation of mass (there's no reason to use that, the question doesn't ask for it).

    since is the same for both particles, and therefore

    it's not conversation of momentum.

    rearranging

    which, when you put the number in, I believe is what the markscheme gives as the answer.

    Please ask if you don't understand.
    albear's Avatar
    albear Posts: 1,594, Reputation: 222
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    #4

    Jun 7, 2007, 12:51 PM
    the mark scheme gets 2.3*10^6m/s

    I get1.7*10^4
    what do u get

    (but it does use MuVu=MpiVpi
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #5

    Jun 7, 2007, 01:02 PM


    I seem to agree with the mark scheme.
    albear's Avatar
    albear Posts: 1,594, Reputation: 222
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    #6

    Jun 7, 2007, 01:06 PM
    Damm my matchs was wrong thanks for helping (I would rate u but still cant)

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