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-   -   PA01 Jan 06 paper (https://www.askmehelpdesk.com/showthread.php?t=99367)

  • Jun 7, 2007, 11:39 AM
    albear
    PA01 Jan 06 paper
    lander=1.2*10^12
    muon mass=207*9.11*10^-31
    muon speed=3*10^6
    neutral pion mass=134.972

    calculate the speed necessary for a (neutral pion) to have the same de Broglie wavelength as that of the muon (lander)

    the mark scheme uses the conservation of momentum, MV(of pion)=MV(of muon)

    yet it ends up with (3*10^6)/1.28 (1.28 is the ratio (rest mass pion)/(rest mass muon))

    I don't understand how it gets this please help quick
  • Jun 7, 2007, 12:14 PM
    albear
    Please any help would be greatly appreciated
  • Jun 7, 2007, 12:33 PM
    Capuchin
    1. It's lambda not lander

    2. i believe it's using (De Broglie Hypothesis) and NOT the conversation of mass (there's no reason to use that, the question doesn't ask for it).

    since is the same for both particles, and therefore

    it's not conversation of momentum.

    rearranging

    which, when you put the number in, I believe is what the markscheme gives as the answer.

    Please ask if you don't understand.
  • Jun 7, 2007, 12:51 PM
    albear
    the mark scheme gets 2.3*10^6m/s

    I get1.7*10^4
    what do u get

    (but it does use MuVu=MpiVpi
  • Jun 7, 2007, 01:02 PM
    Capuchin


    I seem to agree with the mark scheme.
  • Jun 7, 2007, 01:06 PM
    albear
    Damm my matchs was wrong thanks for helping (I would rate u but still cant)

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