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Chemistry homework help
Im very confused with this question
The purity of citric acid was tested Step 1- A sample of 0.48g of citric acid was dissolves in 50cm3 of distilled water Step 2- drops of phenolphthalein indicator was added step 3- It was the titrated with a solution of NaOH (0.50 mol/dm3) Complete: Final burette reading/cm3: 14.60 First burette reading/cm3: 0.20 Volume of NaOH(aq) added/cm3: Pcm3 of NAOH (aq) containing 0.50 moles in 1000cm3 were used. Number of moles NaOH used= 0.5/1000 x P= Q=___________ Number of moles of citric acid in sample= Q/3=R=__________ Relative formula mass of citric acid=_______________ Mass of citric acid in sample=RxMr=S=__________ Percentage purity of sample=S/0.48 x 100=__________% |
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