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thej101 · May 24, 2012, 08:55 PM

-2 root of the square root of 1.573* 10^30.

Please help me solve this problem.

JM

ebaines · May 25, 2012, 04:54 AM

Originally Posted by thej101

-2 root of the square root of 1.573* 10^30.

Please help me solve this problem.

JM

Do you mean this?

$ (\sqrt {1.573 \times 10^{30}})^{-2} $

Remember that taking the square root of something is like raising it to the 1/2 power. So:

$ (\sqrt A)^{-2} = (A^{1/2})^{-2} = A^{(1/2 \times -2)} = A^{-1} = \frac 1 A. $

thej101 · May 25, 2012, 10:02 AM

-2 is outside the square root. For instance, cube root, etc. Also, how would you solve the above problem, if it's a 7 root - outside the square-root- on the v shaped.

Please let me know. The explanation you have provided is not the issue, but how would you solve the above problem is the issue at hand.

Sincerely,
JM

ebaines · May 25, 2012, 10:58 AM

Ok - so this is it:

$ \sqrt[-2] {1.573 \times 10^{30}} $ ?

This type of symbology means you raise the quanity under the root sign to the power 1 over -2. So For example:

$ \sqrt[3] {A} = A^{1/3} $

For your problem you have this:

$ \sqrt[-2] {1.573 \times 10^{30}} = (1.573 \times 10 ^{30})^{-\frac 1 2 } = \frac 1 {\sqrt{1.573}} \times 10 ^{-15}} $

thej101 · May 25, 2012, 09:40 PM

Originally Posted by ebaines

Ok - so this is it:

$ \sqrt[-2] {1.573 \times 10^{30}} $ ?

This type of symbology means you raise the quanity under the root sign to the power 1 over -2. So For example:

$ \sqrt[3] {A} = A^{1/3} $

For your problem you have this:

$ \sqrt[-2] {1.573 \times 10^{30}} = (1.573 \times 10 ^{30})^{-\frac 1 2 } = \frac 1 {\sqrt{1.573}} \times 10 ^{-15}} $

Thank you very much for the clarification. It seems that i was thinking along the same line. For instance, if one understands the concept of square root - square root of X means X ^1/2 or if it's a cube, forth, eight, and so on and forth root, the same principle holds!! If the problem asks us to find the seventh root of X, it could be formatted as follow: X^1/7!!

Sincerely,
JM