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Age problems with solutions?
Jason is now three times as old as Helston.Three years from now,Jason will be six times as old as Helston one year ago. Find their age.
... can you help me? |
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Sure, assign two variables, one for the age of Jason and the other for the age of Helston. Let they be j and h for Jason and Helson respectively. Jason's age is thrice the age of Helston, so you get: j = 3h You have to multiply Helston's age by 3 so that both of their ages equal. Second, Jason will be six times as old as Helston, one year ago, in three years. The age of Jason in 3 years is j+3 That of Helston was h-1 Now, the first age is six times that of the second, once again, multiply the second by 6 so that they both equal, to get: j+3 = 6(h-1) Can you solve those simultaneous equations? |
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Comment on Unknown008's post
ang pagka2alam k kc.. isang variables lng ung kailangan ( x )... saka pano ko sya I-di2vide?
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Comment on Unknown008's post
Pero... I will try to solve it.., thanks for giving me idea :)!.
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Comment on Unknown008's post
Is my answered correct?, Jason's age is 3 yrs. Old while Helston's age is 1 year old?
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No, you didn't get it right. There might be something you missed... can you show your work? |
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Comment on Unknown008's post
J + 3 = 6(h-1)
J+3= 6h-6 J= 6h - 6 - 3 J= 6h -9 substitution: 6h - 9 + 3 = 6h - 6 6h - 6 +6 = 6h 6h/6= 6h/6 h=h or H=1... helston's age J + 3 = 6(1-1) J= 6-3 J = 3 Jason's age Proof: J+3= 6(h-1) 3+3= 6(1-1) 6 = 6 |
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Comment on Unknown008's post
That's my solution... can you say where I was wrong...
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You substituted the wrong equations, and your proof is not good either. In your proof: 3+3= 6(1-1) 6 = 6(0) Anything multiplied by zero gives you 0, so it becomes 6 = 0, which is not true! As a side note, keep your variables consistent, that is if you use small j, use small j everywhere. If you use J, use J everywhere, okay? The equations now: j = 6h -9 j = 3h The substitution becomes: 3h = 6h - 9 3h comes from the second equation and 6h-9 comes from the first equation. Can you try again from there now? :) |
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Let
J= Jason's age h= Helston's age J+3= Jason's age 3yrs from now h-1= Helston's age 1 yr ago. Jason is now three times as old as Helston. J= 3(h) ----> J=3h Three years from now,Jason will be six times as old as Helston one year ago. Find their age. J+3= 6(h-1) ------> J+3= -6+6h J-6h= -6-3 J-6h= -9 J=6h-9 J=3h __________ 3h-9 3h = 9 h = 3 --------- > J-6h=-9 J-6(3)= -9 J-18 = -9 J= 18-9 J= 9 So, Jason is 9 and Helston is 3. :) |
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