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    wallsa17's Avatar
    wallsa17 Posts: 2, Reputation: 1
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    #1

    Dec 1, 2010, 06:06 AM
    Find the exact value for sin(x y) if and . Angles x and y are in the 4thquadrant.
    Remember: to show an identity is true, you have to prove it for all values of a variable. In order to prove that an expression is false, you only need to show one value of the variable that doesn't work. This is called a counterexample.

    Sometimes you have trigonometric equations that are true for some values, but not for others.

    When you provide a counterexample, you are looking for a value which results in an inequality instead of an equality.

    Example:

    Provide a counterexample that proves the equation is not a trigonometric identity.

    Procedure:

    1. Simplify each side as much as possible using trigonometric identities where possible.

    2. Find a value that can be substituted into the equation that makes it an inequality.

    Solution:
    sin0cos0=cos0/sin0
    sin^2 0cos0=cos0
    sin^2 0=cos0/cos0
    sin^2 0=1


    Find a value for θ so sin2 θ ≠ 1.
    If 0=30,sin0 = 1/2 and (1/2)^2=1/4 = 1

    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Dec 1, 2010, 06:42 AM

    The title of your post doesn't seem to match the problem you've worked out here. I assume your use of the characeter "0" iis meant to be , and you are giving an example to show that:



    If so, this looks good. However, the angle you chose for your example (30 degrees) is in the 1st quadrant, not the 4th.

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