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    brea_11's Avatar
    brea_11 Posts: 3, Reputation: 1
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    #1

    Mar 27, 2010, 04:02 PM
    substitution and elimination
    y=3x-8
    y=4-x
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    brea_11 Posts: 3, Reputation: 1
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    #2

    Mar 27, 2010, 04:03 PM

    y=9
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    brea_11 Posts: 3, Reputation: 1
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    #3

    Mar 27, 2010, 04:03 PM
    :mad:
    Quote Originally Posted by brea_11 View Post
    y=9
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    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Mar 28, 2010, 12:10 AM

    No that's not it.

    I'd like to point out that AMHD is not a chat site and you sometimes have to wait before you get an answer.

    The easiest way to solve your equations is by equating them (similar to substitution).

    y=3x-8
    y=4-x

    Which means that :

    y=3x-8 =4-x

    Hence:

    3x-8 =4-x

    Then you solve for x.

    If you want to go for elimination, then subtract the second equation from the first:

    Code:
    y = 3x - 8
y = -x + 4
0 = 4x - 12
    Then you go from there to solve for x.

    When you get x, use that value to solve for y.
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