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    crystal427's Avatar
    crystal427 Posts: 1, Reputation: 1
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    #1

    Mar 10, 2010, 02:29 PM
    Tom and jeremy sold 459 tickets for the Advertising Club's raffle.
    Tom and jeremy sold 459 tickets for the Advertising Club's raffle. If Tom sold 8 times as many tickets as jeremy, how many tickets did each one sell?
    Clough's Avatar
    Clough Posts: 26,677, Reputation: 1649
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    #2

    Mar 10, 2010, 03:19 PM
    Hi, crystal427!

    Are you looking for a direct answer to your question, or for someone to help you to know how to come up with the correct answer yourself, please?

    If the former is true, please read the announcement that can be found via clicking on the following link.

    https://www.askmehelpdesk.com/math-s...-b-u-font.html

    Thanks!
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #3

    Mar 10, 2010, 10:27 PM

    This is a question of ratio, so I'll go with it the easy way, without including variables.

    The ratio of tickets sold by Tom:Jeremy = 8:1

    The total 'parts' is 8+1 = 9.

    So, Tom sold 8/9 of the total tickets, and Jeremy sold 1/9 of the total tickets.

    Can you solve it now?

    Post back your answer.
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