[captain3morgan]

1) y^3 - 4y -8y 2) x^2+2 2x^2-1
--------- . ------------ -------- + --------
16y^2 3y^3-12y 4 5

[captain3morgan]

The second one starts at 4 at the bottom

[galactus]

I hope someone here can figure out what that supposed to be.

Try LaTex. Example:

[morgaine300]

captain3morgan, as you can see, when you post those columns don't stay. We can see it when we do a "quote" of your post, but it won't post that way. You either need to learn the math symbols, or make lots of use of parenthesis and brackets. And then space down a couple of times to clearly separate one problem from another. Doing just that would have helped a lot cause the two problems just ran into each other. Hit the "advance" button and it'll give a preview of what it'll look like, so that you can see if it's reasonably legible to us.

From doing the "quote" so I could see the original, I'm getting this out of the first one:



And this out of the second one:



Can you confirm this is what you mean?

A couple of hints just to get your started. On the first one you need to start by factoring out what you can from the binomials. Then you can start canceling stuff. And keep in mind that you can "cross cancel" cause it's a multiplication.

As for the second one, find a common denominator. Don't let the variables throw you off. A common denominator is a common denominator. If you can do this:

,

then you can do the one above, if you don't let the numerators throw you all off. Just follow the same procedure.

[KISS]

This is what I think the originals look like. The (.) is a multiply.

1)

y^3 - 4y          -8y         
--------- .  ------------                    
16y^2       3y^3-12y                            


2)

x^2+2            2x^2-1
--------      +   --------
4                       5

[morgaine300]

That is exactly what I did.