Factoring quartic functions

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▸ ▸ ▸ ▸ » Factoring quartic functions

kmekme100 Posts: 1, Reputation: 1

New Member

#1

Oct 4, 2009, 03:13 PM

factoring quartic functions

factor fully

f(x) = x^4 - 5x^2 + 4

galactus Posts: 2,271, Reputation: 282

Ultra Member

#2

Oct 4, 2009, 05:05 PM

Let $u=x^{2}$

Then, we get $u^{2}-5u+4$

Now, factor the quadratic and resub.

$u^{2}-5u+4=(u-4)(u-1)$

Since $u=x^{2}$ , resub:

$(x^{2}-4)(x^{2}-1)$

Note the difference of two squares in both.

$(x+2)(x-2)(x+1)(x-1)$

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