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New Member
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Sep 17, 2009, 05:35 PM
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Factoring in Advanced Functions Grade 12
How do you factor 4x²-10x+6?
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Expert
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Sep 18, 2009, 06:24 AM
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It will require a little perseverance:
1. Since the middle term is minus and the last term is positive, this means that the two factors must be of the form (ax-b)*(cx-d); that is, there's a minus sign in each. Do you see why?
2. The middle term, -10, comes from ad+bc. So now the trick is to look at the possible values for a, b, c, and d that satisfy this. First, 4=ac, so a and c can be either 4 and 1 (in either order) or 2 and 2. Second, 6=bd, so b and d can be either 6 and 1 or 2 and 3 (in either order). So now it's a matter of trying all these combinations and finding one that works. There is one, so keep at it! Post back if you're still having trouble.
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New Member
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Oct 29, 2009, 07:19 AM
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(x+y)^2-64
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New Member
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Oct 29, 2009, 07:20 AM
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how do I factor (x+y)^2-64
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Uber Member
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Oct 29, 2009, 08:09 AM
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You should have started another thread, mrsu...
Ok, look at it carefully, you have the difference of two perfect squares, right?
Well you should know that
Use that to solve your problem. :)
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New Member
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Nov 18, 2009, 01:52 PM
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(x+y-8)*(x+y+8) difference of squares
let a=x+y & b=8
a^2-b^2=(a-b)*(a+b)
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New Member
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Mar 3, 2010, 08:07 PM
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 Originally Posted by ebaines
It will require a little perseverance:
1. Since the middle term is minus and the last term is positive, this means that the two factors must be of the form (ax-b)*(cx-d); that is, there's a minus sign in each. Do you see why?
2. The middle term, -10, comes from ad+bc. So now the trick is to look at the possible values for a, b, c, and d that satisfy this. First, 4=ac, so a and c can be either 4 and 1 (in either order) or 2 and 2. Second, 6=bd, so b and d can be either 6 and 1 or 2 and 3 (in either order). So now it's a matter of trying all these combinations and finding one that works. There is one, so keep at it! Post back if you're still having trouble.
x=1 or x-1.5
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New Member
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Mar 3, 2010, 08:08 PM
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x=1 or x=1.5
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