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    jonesm2's Avatar
    jonesm2 Posts: 2, Reputation: 1
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    #1

    Sep 9, 2009, 02:48 PM
    Solving functions
    If f(x)= the square root of x, g(x)= 6x-3, and h(x)= x/3

    what does f(g(h(6))) equal? And how do you do this?
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Sep 10, 2009, 09:31 AM

    Ok;







    To solve for f(g(h(6))), you need to find the value for h(6) first. To do that, replace the 'x' in h(x) by 6.

    You'll have:



    Now, you need to find g(h(6)). This s done by replacing the 'x' in g(x) by the value of h(6):



    Can you continue? :)

    Post the final answer if you please.
    jonesm2's Avatar
    jonesm2 Posts: 2, Reputation: 1
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    #3

    Sep 10, 2009, 01:36 PM

    Thanks! I got a 100 on my test today :)
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Sep 11, 2009, 11:11 AM

    Hey Congrats! :) I was glad to help! :)
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