If f(x)= the square root of x, g(x)= 6x-3, and h(x)= x/3
what does f(g(h(6))) equal? And how do you do this?
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If f(x)= the square root of x, g(x)= 6x-3, and h(x)= x/3
what does f(g(h(6))) equal? And how do you do this?
Ok;
To solve for f(g(h(6))), you need to find the value for h(6) first. To do that, replace the 'x' in h(x) by 6.
You'll have:
Now, you need to find g(h(6)). This s done by replacing the 'x' in g(x) by the value of h(6):
Can you continue? :)
Post the final answer if you please.
Thanks! I got a 100 on my test today :)
Hey Congrats! :) I was glad to help! :)
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