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murraytiger2012 · Jul 30, 2009, 10:45 AM

A car is traveling at a constant velocity. After two hours the car has traveled 110 miles. After four hours the car has traveled 220 miles. Assuming a linear equation fits this situation, find the linear equation for the given data.

Unknown008 · Jul 30, 2009, 10:54 AM

You have all the required data, you can do it easily.

You have two points, well they are disguised.

I'll say let distance be y, and time be x.

$x_1 = 2$ and $y_1 = 110$

Those are the first pieces of information you are given, and you may represent them as (2, 110)

Then,

$x_2 = 4$ and $y_2 = 220$

Again, you have (4, 220)

You have two points, use the formula $\frac{y_2-y_1}{x_2-x_1} = m$ to find the gradient m.

Then to have the equation, use: $\frac{y-(y-coordinate)}{x-(x-coordinate)} = m$

Hope it helped! :)