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    angie160's Avatar
    angie160 Posts: 1, Reputation: 1
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    #1

    Oct 29, 2008, 04:55 PM
    ALGEBRA; x and y intercepts
    OK the problem is:

    2x-3y=24

    they want me to find the x and the y intercept.
    I forget how to do this kind of problem.
    please help me by explaining the steps, if someone can just remind me I'm pretty sure I'll remember how to do it.
    Khianu's Avatar
    Khianu Posts: 6, Reputation: 3
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    #2

    Oct 29, 2008, 05:09 PM
    x and y intercepts are the points at which a graph crosses the axis, i.e. the x intercept is where the line crosses the x axis. Now the x axis is definitively where the y value is equal to zero. Likewise the y axis is the line where x=0 as you could see by looking at a basic set of axis. This means that to find the x intercept you simply set the y value to be 0, and thus get out an x value. This value is x co-ordinate of the graph when y=0 and the line crosses the x axis, and likewise for y. Sounds quite complicated so:

    To find the x intercept:
    1. substitute y for 0 in the equation
    2. rearrange the equation to get x=...
    3. this value (... ) is the x intercept, and the co-ordinates for the point where it crosses the axis is (.. 0)

    likewise to find the y intercept:
    1. substitute x for 0 in the equation
    2. rearrange to get y=...
    3. this value (... ) is the y intercept, and the co-ordinates for the point where it crosses the axis is (0,. )

    Hope this has been clear enough but will try my best to explain differently if you still have trouble. Thanks.

    Ben

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