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    kabraham's Avatar
    kabraham Posts: 11, Reputation: 1
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    #1

    Sep 7, 2008, 12:08 PM
    Find the sum of all the integers from 150 to 366.
    Find the sum of all the integers from 150 to 366.
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #2

    Sep 7, 2008, 01:06 PM
    Use the formula for the sum of the n integers and subtract them.

    for the integers up to 149

    Then do the same for 366

    Then subtract the two results.
    kabraham's Avatar
    kabraham Posts: 11, Reputation: 1
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    #3

    Sep 7, 2008, 01:16 PM
    Quote Originally Posted by kabraham
    Find the sum of all the integers from 150 to 366.
    I don't understand what your have there
    What answer you got let me compare it to my answer
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #4

    Sep 7, 2008, 01:18 PM
    What's your answer? I just gave the formula for the sum of the first n integers.

    Well-known if you're studying sequences.
    BlakeCory's Avatar
    BlakeCory Posts: 236, Reputation: 21
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    #5

    Sep 7, 2008, 01:20 PM
    Quote Originally Posted by kabraham
    What answer you [did you get,] let me compare it to my answer.
    If you post your answer we can help you with it, we can't just give you the answer, then we would be doing your homework.
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    kabraham Posts: 11, Reputation: 1
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    #6

    Sep 7, 2008, 01:22 PM
    Quote Originally Posted by kabraham
    Find the sum of all the integers from 150 to 366.
    My answer is 55836
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #7

    Sep 7, 2008, 02:00 PM
    You're off by 150. Should be 55986.

    That is why we sum from 1 to 149 and then 1 to 366 and subtract.





    67161-11175=55986

    See?
    kabraham's Avatar
    kabraham Posts: 11, Reputation: 1
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    #8

    Sep 7, 2008, 02:13 PM
    Quote Originally Posted by kabraham
    Find the sum of all the integers from 150 to 366.
    Evaluate the sum of the first 125 terms of the series whose nth term is equal to (2 n - 12).
    Could you help me with this one also
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #9

    Sep 7, 2008, 04:15 PM
    The nth term is 2n-12. So, if we look at it, we are summing up the even integers from -10 to 238.

    -10-8-6-4-2-0+2+4+6+8+... +238

    The nth partial sum is given by

    Where n=125 and
    kabraham's Avatar
    kabraham Posts: 11, Reputation: 1
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    #10

    Sep 7, 2008, 04:35 PM
    Quote Originally Posted by kabraham
    Find the sum of all the integers from 150 to 366.
    That's the answer your got
    kabraham's Avatar
    kabraham Posts: 11, Reputation: 1
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    #11

    Sep 7, 2008, 04:47 PM
    Quote Originally Posted by kabraham
    Find the sum of all the integers from 150 to 366.
    I got the answer for the previous one. Thanks a lot man I really appreciate it very much could you help with this one I got this answer 2.3

    Find the infinite sum of the sequence
    10, −3, 0.9, −0.27, 0.0809999999999999, …

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