Find the sum of all the integers from 150 to 366.

Use the formula for the sum of the n integers and subtract them.

for the integers up to 149

Then do the same for 366

Then subtract the two results.

Quote:

---

Originally Posted by kabraham

Find the sum of all the integers from 150 to 366.

---

I don't understand what your have there
What answer you got let me compare it to my answer

What's your answer? I just gave the formula for the sum of the first n integers.

Well-known if you're studying sequences.

Quote:

---

Originally Posted by kabraham

What answer you [did you get,] let me compare it to my answer.

---

If you post your answer we can help you with it, we can't just give you the answer, then we would be doing your homework.

Quote:

---

Originally Posted by kabraham

Find the sum of all the integers from 150 to 366.

---

My answer is 55836

You're off by 150. Should be 55986.

That is why we sum from 1 to 149 and then 1 to 366 and subtract.





67161-11175=55986

See?

Quote:

---

Originally Posted by kabraham

Find the sum of all the integers from 150 to 366.

---

Evaluate the sum of the first 125 terms of the series whose nth term is equal to (2 n - 12).
Could you help me with this one also

The nth term is 2n-12. So, if we look at it, we are summing up the even integers from -10 to 238.

-10-8-6-4-2-0+2+4+6+8+... +238

The nth partial sum is given by

Where n=125 and

Quote:

---

Originally Posted by kabraham

Find the sum of all the integers from 150 to 366.

---

That's the answer your got

Quote:

---

Originally Posted by kabraham

Find the sum of all the integers from 150 to 366.

---

I got the answer for the previous one. Thanks a lot man I really appreciate it very much could you help with this one I got this answer 2.3

Find the infinite sum of the sequence
10, −3, 0.9, −0.27, 0.0809999999999999, …