[shammaym]

I have 4 qustions that should be solved.
Q 1 :
A sphere rolling with an initial velocity of 9 m/s
starts uo a plane inclined at 30 degrees.
How far up the plane will the sphere roll
For sphere I= 3/5 mr2

Q 2 :
A steel bar 75mm diameter, starts from rest and roll
without slipping down a plane inclined at 10 degrees
to the horizontal, the mass of the bar is 85kg.
Find the kinetic energy of the bar when it has rolled
6m down the slope.

Q 3 :
Suppose a flywheel A,has a mass of 2kg, a radius of
0.20m and an initial angular velocity of 50 rad/s and
that a clutch plate B has a mass of 4kg and a radius
of 0.1m and an initial angular velocity (w) after the
disks are pushed into contact.

Q 4 :
A ball has a mass of 0.145 kg.

A) It the velocity of a pitched ball is 30m/s, and
after the ball is batted the velocity is 50 m/s in the
opposite direction,
Find the magnitude of the change in momentum of the
ball and the impulse applied to it by the bat.

B) It the ball remains in contact with the bat for
0.002s
Find the magnitude of the average force applied by the
bat

IF YOU CAN HELP BY ANSWERING THESE QUSTIONS,IT WILL BE
GREAT FROM YOU AND A GOOD HELP
THANKS A lot
YOUSEF

[i_need_help]

provide the necessary physics equations and I'll solve them, I forget the equations.

for instance, what's the kinematic equations? What's the kinetic energy equations?

[shammaym]

Thanks a lot for your reply
I have some equations that can help you to answer these 4 qustions .
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Momentum (p) = mas x velocity
Momentum (p) = M X V
the unit in ( KG.M/S )
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Impules (G) = applied force x duration of applicatin
Impules (G) = F X T
the unit in ( NS )

******************************
Angular momentum = L (w ) = I X w-----> omiga

************************************
work done = F X S -----------> for liners

work done = T X Q -----------> for liners

**********************************
PE (potental energy) = mgh

********************************

KE (KINETIC ENERGY)= 1/2 mv2 - number 2 is power for v

****************************
thanks a lot for anybody can help me