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    lollive's Avatar
    lollive Posts: 1, Reputation: 1
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    #1

    Jun 3, 2008, 02:17 PM
    Math
    Can anyone help me with this math word problem please.America west airlines has 3 models of boeing aircraft in their fleet.the 737-300 contains 21 more seats than the 737-200 The 757-200 contains 36 less than twice the number of seats in the 737-200. Find the number of seats for the 3 if the total number of seats for all is 437
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Jun 3, 2008, 02:44 PM
    You need to set up 3 equations isn't 3 unknowns. Let's define A as the number of seats on the 737-300, B is the number of seats on the 737-200, and C is the number of seats on the 757-200. From the statement that "the 737-300 contains 21 more setas than the 737-200" you get:

    A = 21+B

    From "the 757-200 contains 36 less than twice the number of seats in the 737-200" you get:

    C = 2*B - 36

    And finally the last sentence of the problem tells you that A+B+C = 437. Now you have the three equationas, and you should be able to solve them.

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