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    nmsavage's Avatar
    nmsavage Posts: 1, Reputation: 1
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    #1

    Feb 5, 2008, 02:07 PM
    trig identities
    prove (1+tanx)/(sinx+cosx) = secx
    SirOracle's Avatar
    SirOracle Posts: 11, Reputation: 1
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    #2

    Feb 5, 2008, 09:44 PM
    well, to separate it out:

    1 + tanx = 1 + sinx/cosx = cosx/cosx + sinx/cosx = (cosx + sinx)/cosx

    so when this is divided by (sinx + cosx), the numerator cancels, leaving:

    1/cosx = secx
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