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    puttybro's Avatar
    puttybro Posts: 1, Reputation: 1
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    #1

    Nov 12, 2007, 11:22 AM
    Calculating Electrical Load Non-Occupied Home
    Help! I am trying to qualify for an Ag rate on a non-occupied country home. The home is 2100 square feet and has a full kitchen and washer/dryer. It also has a swimming pool with a cleaner and a hot tub. The oven and hot tub are powered by propane. All heat is by gas stove and no air conditioning. The big point is the home is UNOCCUPIED/VACANT. Our electrical usage is limited to the pump for our well which waters our vineyards in the summer. We are on a residential rate and it's killing us (av $800/mo in summer!). We want to qualify for an ag rate but to do so we need to send them our electrical load. I want to be accurate but following instructions for typical load isn't right since we never use the home/appliances. Any ideas??
    tkrussell's Avatar
    tkrussell Posts: 9,659, Reputation: 725
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    #2

    Nov 12, 2007, 02:08 PM
    Can you show exactly what the AG agency is asking for?

    Calculating load is done to determine the size service entrance equipment is required, I do not think that is what is needed.


    What size pump do you have? How much time is it on? That is one heck of an electric bill.
    KISS's Avatar
    KISS Posts: 12,510, Reputation: 839
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    #3

    Nov 12, 2007, 08:15 PM
    The (hot tub heaters and pumps) are significant loads, so is the pool filter motor and the well pump.

    I think you need nameplate values of HP, VA, Watts and the approximate duty cycle of the loads in a 30 day period. You should be able to come up with the approximate KWH as the electric bill. 1 HP = 746 Watts. VA is volt-amps and can be casually accepted as Watts.

    Example:

    1/3*746*30*24/1000*0.15

    1/3 HP * 746 W/HP * 24 hr/day * 24 days/1000 = Kwh

    Multiply by electric rate of say 0.15/KWH = $26.86/month
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