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-   -   Calculating Electrical Load Non-Occupied Home (https://www.askmehelpdesk.com/showthread.php?t=151218)

  • Nov 12, 2007, 11:22 AM
    puttybro
    Calculating Electrical Load Non-Occupied Home
    Help! I am trying to qualify for an Ag rate on a non-occupied country home. The home is 2100 square feet and has a full kitchen and washer/dryer. It also has a swimming pool with a cleaner and a hot tub. The oven and hot tub are powered by propane. All heat is by gas stove and no air conditioning. The big point is the home is UNOCCUPIED/VACANT. Our electrical usage is limited to the pump for our well which waters our vineyards in the summer. We are on a residential rate and it's killing us (av $800/mo in summer!). We want to qualify for an ag rate but to do so we need to send them our electrical load. I want to be accurate but following instructions for typical load isn't right since we never use the home/appliances. Any ideas??
  • Nov 12, 2007, 02:08 PM
    tkrussell
    Can you show exactly what the AG agency is asking for?

    Calculating load is done to determine the size service entrance equipment is required, I do not think that is what is needed.


    What size pump do you have? How much time is it on? That is one heck of an electric bill.
  • Nov 12, 2007, 08:15 PM
    KISS
    The (hot tub heaters and pumps) are significant loads, so is the pool filter motor and the well pump.

    I think you need nameplate values of HP, VA, Watts and the approximate duty cycle of the loads in a 30 day period. You should be able to come up with the approximate KWH as the electric bill. 1 HP = 746 Watts. VA is volt-amps and can be casually accepted as Watts.

    Example:

    1/3*746*30*24/1000*0.15

    1/3 HP * 746 W/HP * 24 hr/day * 24 days/1000 = Kwh

    Multiply by electric rate of say 0.15/KWH = $26.86/month

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