[princessgloomy]

Yeah I really don't know how to do this:


A point is equidistant from points A(2,1), B(2,-4), and C(-3,1). Find its coordinates.



Help! I need somebody! Not just anybody! Help! (Beatles :D )

[ebaines]

First thing is to think about what points are equidistant from A and B. Since both of these points have the same x-coordinate, all the points on the horizontal line whose y value is the average of the y values of points A and B are equidistant from both A and B. Consequently the line y= -1.5 is equidistant from both A and B. Can you see that? OK, now think about points that are equidistant from both A and C - again, these points are all on a line. Once you determine what that line is, the one point that is equidistant from A, B and C is at the intersection of the two lines. Hope this helps.

[princessgloomy]

Well the answer I got is (-1/2, -2 1/2)?

Hope it's correct. Thank you.

[ebaines]

Your x-coordinate is correct, but the y coordinate is not. Check your work. I suggest that when you think you have the answer check it by calculating the distance between that point and A,B and C to make sure the distances are all equal.