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-   -   How to Find Equidistant (https://www.askmehelpdesk.com/showthread.php?t=147440)

  • Nov 1, 2007, 11:24 AM
    princessgloomy
    How to Find Equidistant
    Yeah I really don't know how to do this:


    A point is equidistant from points A(2,1), B(2,-4), and C(-3,1). Find its coordinates.



    Help! I need somebody! Not just anybody! Help! (Beatles :D )
  • Nov 1, 2007, 11:34 AM
    ebaines
    First thing is to think about what points are equidistant from A and B. Since both of these points have the same x-coordinate, all the points on the horizontal line whose y value is the average of the y values of points A and B are equidistant from both A and B. Consequently the line y= -1.5 is equidistant from both A and B. Can you see that? OK, now think about points that are equidistant from both A and C - again, these points are all on a line. Once you determine what that line is, the one point that is equidistant from A, B and C is at the intersection of the two lines. Hope this helps.
  • Nov 1, 2007, 11:44 AM
    princessgloomy
    Well the answer I got is (-1/2, -2 1/2)?

    Hope it's correct. Thank you.
  • Nov 1, 2007, 11:51 AM
    ebaines
    Your x-coordinate is correct, but the y coordinate is not. Check your work. I suggest that when you think you have the answer check it by calculating the distance between that point and A,B and C to make sure the distances are all equal.

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