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    MsTaylor23's Avatar
    MsTaylor23 Posts: 41, Reputation: 1
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    #1

    Jun 20, 2007, 08:26 AM
    Solve Interval Nation
    3x<=6x-9/3<+10 The question

    My answer

    3x<=2x-9<=10

    3x<=2x-9 or 2x-9<=10

    3x+9<=2
    9<=2x-3
    x=>-9


    or

    2x-9<=10
    2x<=10+9
    2x=19 divide both sides by 2

    x<=9 1/2

    I think I made more of this than it is
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Jun 20, 2007, 08:44 AM
    MsTaylor23: it seems that your posting has multiple typos, so that it's impossible to help you on this. Please restate the original problem - is it:

    3x < 6x/3 - 9 < 10

    or is it:

    3x< (6x-9)/3 < 10

    or is it:

    3x < 6x - 9/3 < 10? Please take care to type it out properly.

    Also, you seem to alternately leave out or put in an "x" here and there, making it impossible to follow along. Please clarify - thanks!
    MsTaylor23's Avatar
    MsTaylor23 Posts: 41, Reputation: 1
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    #3

    Jun 20, 2007, 08:46 AM
    It is the third one. I am still new to this and its complicating to type this problems out on here.
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #4

    Jun 20, 2007, 08:54 AM
    OK. Then the first step is:

    3x <= 6x -9/3 <= 10
    3x <= 6x - 3 <= 10

    Then divide through by 3:

    x <= 2x -1 <= 10/3

    Can you continue from there?
    MsTaylor23's Avatar
    MsTaylor23 Posts: 41, Reputation: 1
    Junior Member
    		  
    #5

    Jun 20, 2007, 09:19 AM
    The answer I got from it was x=>1 or x<=13/6.

    I separated them as x<=2x-1 or 2x-1<=10/3.
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #6

    Jun 20, 2007, 09:26 AM
    Right. Now you can put the two expressions together to get:

    1<= x <= 13/6
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