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    blackpalm's Avatar
    blackpalm Posts: 1, Reputation: 1
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    #1

    Sep 15, 2010, 06:39 PM
    Calculate: Heating 235 g of water from 22.6 degrees C to 94.4 degrees C in a microwav
    I guess we must use c=lambda*frequency...
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Sep 15, 2010, 10:38 PM

    Actually... no.



    is used to find the frequency or wavelength of an electromagnetic wave if either the wavelength or the frequency is known.

    Here, I guess that you are looking for the amount of heat that the water gains.

    This is given by:



    Q is the amount of heat in joules
    m is the mass of the substance
    c is the specific heat capacity of water (which you must be given)
    and theta is the change in temperature in Kelvin.

    Can you work this out now? :)
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