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Jordana21 · Apr 29, 2009, 03:18 PM

Help! For the life of me I can't figure out how to get the quadratic equation out of this.:confused:

A jet flew from Tokyo to Bangkok, a distance of 4800 km. On the return trip, the speed was decreased by 200 km/h. If the difference in the times of the flights was 2 hours, what was the jet's speed from Bangkok to Tokyo? (13 marks)

Thanks in advance

Unknown008 · Apr 30, 2009, 11:08 AM

First of all, let's introduce the unknown terms;

let the speed from Tokyo to Bangkok be $x$
On the return trip, the speed will be $x-200$

$Speed=\frac{Distance}{Time}$

$Time=\frac{Distance}{Speed}$

So,

$\frac{4800}{x} + 2 = \frac{4800}{x-200}$

Can you solve it from here?

Jordana21 · Apr 30, 2009, 02:31 PM

Originally Posted by Unknown008

First of all, let's introduce the unknown terms;

let the speed from Tokyo to Bangkok be $x$
On the return trip, the speed will be $x-200$

$Speed=\frac{Distance}{Time}$

$Time=\frac{Distance}{Speed}$

So,

$\frac{4800}{x} + 2 = \frac{4800}{x-200}$

Can you solve it from here?

Yes I think I've got it from there. I was getting stuck on what to write for the time, but that makes sense, thanks!

Unknown008 · Apr 30, 2009, 08:34 PM

No, that's OK. I was glad to help! See you around! :)