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    bryanna19's Avatar
    bryanna19 Posts: 5, Reputation: 1
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    #1

    Mar 17, 2008, 05:25 AM
    trig identities
    I am supposed to use the double-angle identitie for this one and solve sin(x) to equal 2sin(x), I no the answer but it's the process I don't get.. can anyone help?
    ISneezeFunny's Avatar
    ISneezeFunny Posts: 4,175, Reputation: 821
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    #2

    Mar 17, 2008, 05:28 AM
    well the formulas for the double angles are here:

    Double-Angle Formulas -- from Wolfram MathWorld

    I'm not entirely sure what you have to solve..

    sin x = 2sin x?
    bryanna19's Avatar
    bryanna19 Posts: 5, Reputation: 1
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    #3

    Mar 17, 2008, 05:47 AM
    well I have to work one side till it looks like the other using the double angle identities that you have from that site. And yes that equation is what it looks like
    ISneezeFunny's Avatar
    ISneezeFunny Posts: 4,175, Reputation: 821
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    #4

    Mar 17, 2008, 05:49 AM
    OH. Well...

    sin x = 2 sin x

    doesn't make sense. As they're not equal. At all.

    unless they both equal 0.
    bryanna19's Avatar
    bryanna19 Posts: 5, Reputation: 1
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    #5

    Mar 17, 2008, 05:51 AM
    actually wait... its sin2x=2sinx and solve using double angle identities.. sorry I looked at it wrong.. does that work>?
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    bryanna19 Posts: 5, Reputation: 1
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    #6

    Mar 17, 2008, 05:52 AM
    And just keep solving one side till it looks like the other
    ISneezeFunny's Avatar
    ISneezeFunny Posts: 4,175, Reputation: 821
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    #7

    Mar 17, 2008, 05:54 AM
    are you sure that's the problem..

    as sin (2x) = 2 sin (x) cos (x)
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