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-   -   Trig identities (https://www.askmehelpdesk.com/showthread.php?t=195454)

  • Mar 17, 2008, 05:25 AM
    bryanna19
    trig identities
    I am supposed to use the double-angle identitie for this one and solve sin(x) to equal 2sin(x), I no the answer but it's the process I don't get.. can anyone help?
  • Mar 17, 2008, 05:28 AM
    ISneezeFunny
    well the formulas for the double angles are here:

    Double-Angle Formulas -- from Wolfram MathWorld

    I'm not entirely sure what you have to solve..

    sin x = 2sin x?
  • Mar 17, 2008, 05:47 AM
    bryanna19
    well I have to work one side till it looks like the other using the double angle identities that you have from that site. And yes that equation is what it looks like
  • Mar 17, 2008, 05:49 AM
    ISneezeFunny
    OH. Well...

    sin x = 2 sin x

    doesn't make sense. As they're not equal. At all.

    unless they both equal 0.
  • Mar 17, 2008, 05:51 AM
    bryanna19
    actually wait... its sin2x=2sinx and solve using double angle identities.. sorry I looked at it wrong.. does that work>?
  • Mar 17, 2008, 05:52 AM
    bryanna19
    And just keep solving one side till it looks like the other
  • Mar 17, 2008, 05:54 AM
    ISneezeFunny
    are you sure that's the problem..

    as sin (2x) = 2 sin (x) cos (x)

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