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StephPre · Jan 20, 2008, 05:00 AM

Log3(x+2)+ Log3(x-1)-2

ebaines · Jan 21, 2008, 10:10 AM

Do you mean:

$<br /> log_3 {(x+2)}\ +\ log_3{(x-1)}\ -\ 2?<br />$

First, try to get everything written in the same log base. Note that:

$2 = log_3 9$

and combine that with the property that log(abc) = log(a) + log(b) + log(c). So you have:

$<br /> log_3 {(x+2)}\ +\ log_3{(x-1)}\ -\ 2\ =\ log_3 {(x+2)} +log_3 {(x-1)} +log_3 9 = log_3 {[9(x+2)(x-1)]}<br />$

Gloriouss · Jan 21, 2008, 10:19 AM

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