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    my hobbie's Avatar
    my hobbie Posts: 1, Reputation: 1
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    #1

    Dec 6, 2007, 09:47 PM
    mole-mole ratios
    :confused: Given the fallowing balanced equation, 2Al + 3S -> Al2S3
    Q 1. How many moles of Al2S3 will form if we start with 16 moles of Al?
    Q 2. How many moles of sulfur will be combined with 16 moles of Al?
    :confused:
    kp2171's Avatar
    kp2171 Posts: 5,318, Reputation: 1612
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    #2

    Dec 6, 2007, 10:04 PM
    See the reaction? It tells you that 2 moles of al are needed to form one mole of al2s3... right? So...

    Do the work and well talk about your answer.
    jasejase's Avatar
    jasejase Posts: 3, Reputation: 1
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    #3

    Dec 7, 2007, 11:02 AM
    Quote Originally Posted by my hobbie
    :confused: Given the fallowing balanced equation, 2Al + 3S -> Al2S3
    Q 1. How many moles of Al2S3 will form if we start with 16 moles of Al?
    Q 2. How many moles of sulfur will be combined with 16 moles of Al?
    :confused:
    Just use the mole ratio for Al:Al2S3.
    It is 2:1. Take this to mean, for every 2 moles of Al, we get one mole of AL2S3.
    If we start with 16 moles of Al, we will get 8 moles of Al2S3.
    As for the second question, just multiply the 16 by 1.5 to get 24 moles of Sulphur per mole of Aluminum.
    itsme_vipsdude's Avatar
    itsme_vipsdude Posts: 29, Reputation: 0
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    #4

    Dec 12, 2007, 02:44 AM
    Ans 1 - 8
    Ans 2- 24
    kp2171's Avatar
    kp2171 Posts: 5,318, Reputation: 1612
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    #5

    Dec 12, 2007, 03:02 PM
    Quote Originally Posted by itsme_vipsdude
    ans 1 - 8
    ans 2- 24
    Please review the rules of the site. AMHD requests that we do NOT flat out provide answers to problems. It is why I didn't answer it in the first post of the thread.

    https://www.askmehelpdesk.com/math-s...-b-u-font.html

    Yes, it takes more time and effort to talk someone through a problem, but if they are not willing to do the work, then they aren't willing to learn.

    Glad you want to help. Its why we log on.

    But try not to give people answers when they are simply posting the question without a thoughtful discussion.
    Berstas's Avatar
    Berstas Posts: 3, Reputation: 1
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    #6

    Mar 22, 2008, 12:17 PM
    Comment on kp2171's post
    I do not find this answer helpful whatsoever. It is much simpler.. you are overthinking.
    Berstas's Avatar
    Berstas Posts: 3, Reputation: 1
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    #7

    Mar 22, 2008, 12:19 PM
    Comment on jasejase's post
    Yes! Great explanation.. kudos!

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