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    malic's Avatar
    malic Posts: 11, Reputation: 2
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    #1

    Nov 28, 2007, 06:05 PM
    Baseball thrown up
    A 0.150 kg baseball is thrown upward with an initial speed od 20.0 m/s

    Questions:
    a. what is the force on the ball when it reaches half of its maximum height? (disreguard air resistance)
    b. what is the force on the ball when I reaches its peak?

    Please help. I'm so lost right now.
    tjsail's Avatar
    tjsail Posts: 12, Reputation: 4
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    #2

    Nov 28, 2007, 06:26 PM
    Quote Originally Posted by malic
    a 0.150 kg baseball is thrown upward with an initial speed od 20.0 m/s

    questions:
    a. what is the force on the ball when it reaches half of its maximum height? (disreguard air resistance)
    b. what is the force on the ball when i reaches its peak?

    please help. i'm so lost right now.
    This looks like a trick question aimed at measuring your confusion. If you disregard air resistance, the only force on it is the weight. So the answer to both a. and b. is

    W = m*g = 0.150 kg*9.8 m/s^2 = 1.47 kg*m/s^2 = 1.47 Newtons
    malic's Avatar
    malic Posts: 11, Reputation: 2
    New Member
    		  
    #3

    Nov 28, 2007, 06:40 PM
    Quote Originally Posted by tjsail
    This looks like a trick question aimed at measuring your confusion. If you disregard air resistance, the only force on it is the weight. So the answer to both a. and b. is

    W = m*g = 0.150 kg*9.8 m/s^2 = 1.47 kg*m/s^2 = 1.47 Newtons
    Thank you so much
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