A 0.150 kg baseball is thrown upward with an initial speed od 20.0 m/s

Questions:
a. what is the force on the ball when it reaches half of its maximum height? (disreguard air resistance)
b. what is the force on the ball when I reaches its peak?

Please help. I'm so lost right now.

Quote:

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Originally Posted by malic

a 0.150 kg baseball is thrown upward with an initial speed od 20.0 m/s

questions:
a. what is the force on the ball when it reaches half of its maximum height? (disreguard air resistance)
b. what is the force on the ball when i reaches its peak?

please help. i'm so lost right now.

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This looks like a trick question aimed at measuring your confusion. If you disregard air resistance, the only force on it is the weight. So the answer to both a. and b. is

W = m*g = 0.150 kg*9.8 m/s^2 = 1.47 kg*m/s^2 = 1.47 Newtons

Quote:

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Originally Posted by tjsail

This looks like a trick question aimed at measuring your confusion. If you disregard air resistance, the only force on it is the weight. So the answer to both a. and b. is

W = m*g = 0.150 kg*9.8 m/s^2 = 1.47 kg*m/s^2 = 1.47 Newtons

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Thank you so much