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gmh69 · Oct 2, 2007, 01:38 PM

Given x^2-y^2, find dy/dx by implicit differentiation

rebel-2 · Oct 3, 2007, 04:57 AM

Given x^2-y^2, find dy/dx by implicit differentiation

Hello there do you mean y=x²-y²
my knowledge is limited but i think this is how you do it, lmao.:D

y=x²-y²
dy/dx=2x-2y

and that's all for differentiation, i think... use nx^n-1.

Mabey someone else here will explain this to us

galactus · Oct 3, 2007, 02:17 PM

Is that $x^{2}-y^{2}=0$ ?

Is it $y=x^{2}-y^{2}$

$y=x^{2}-y^{2}$

$y-x^{2}+y^{2}=0$

$\frac{dy}{dx}-2x+2y\frac{dy}{dx}=0$

Solve for dy/dx:

$\fbox{\frac{dy}{dx}=\frac{2x}{1+2y}}$