Given x^2-y^2, find dy/dx by implicit differentiation
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Given x^2-y^2, find dy/dx by implicit differentiation
Hello there do you mean y=x²-y²Quote:
Given x^2-y^2, find dy/dx by implicit differentiation
my knowledge is limited but i think this is how you do it, lmao.:D
y=x²-y²
dy/dx=2x-2y
and that's all for differentiation, i think... use nx^n-1.
Mabey someone else here will explain this to us
Is that?
Is it
Solve for dy/dx:
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