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    loire77's Avatar
    loire77 Posts: 1, Reputation: 1
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    #1

    Feb 16, 2013, 11:31 PM
    verifying trigonometric identities solver free
    cos^2x-cot^2x=cos^2xcot^2x

    (1-cosx)/(1+cosx)=(cotx-cscx)^2

    1/tanx-secx+1/tanx+secx=-2tanx

    sec^4x-sec^2x=tan^4x+tan^4x

    cosx/1-sinx=1+sinx/cosx

    1-secxcosx=tanxcotx-1

    sinx+cosx=secx+cscx/cscx+secx

    sinx=sin^3+cos^2xsinx

    sinx+cosx+1=2sinxcosx/sinx+cosx-1
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Feb 18, 2013, 08:13 AM
    In almost all cases the way to approach these problems is to first convert tangent, cotangent, secant, and cosecant function to their sine and cosine equivalents, and then simplify the expression. You also may have to apply a few key identites that you must be familiar with, such as:

    sin^2x +cos^2x = 1
    sin2x = 2sinx cosx
    cos2x = cos^2x - sin^2x = 2 cos^2x - 1 = 1 - 2 sin^2x

    Memorize these and look for opportunities to apply them.
    MDAncell's Avatar
    MDAncell Posts: 1, Reputation: 1
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    #3

    Apr 5, 2013, 01:56 PM
    Verify
    csc(x)cos^(2)(x)+sin(x)=csc(x)
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #4

    Apr 5, 2013, 02:34 PM
    Quote Originally Posted by MDAncell View Post
    Verify
    csc(x)cos^(2)(x)+sin(x)=csc(x)
    See the advice given earlier in post #2 - it works well on this problem.
    elisa2520's Avatar
    elisa2520 Posts: 1, Reputation: 1
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    #5

    Apr 7, 2013, 01:25 PM
    verify each

    (sin 2x) (sec x) (csc x)=2

    (sin 2x)^2=4 (1-sin^2 x-cos^4x)

    prove:

    sin 2x cosx=2 (sinx-sin3x)
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #6

    Apr 8, 2013, 05:57 AM
    elisa2520: each of these can be solved if you apply the identity for sin(2x) - you should memorize this:



    You will also have to apply the fundamental identity and its variations (e.g. ).

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