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-   -   Verifying trigonometric identities solver free (https://www.askmehelpdesk.com/showthread.php?t=734607)

  • Feb 16, 2013, 11:31 PM
    loire77
    verifying trigonometric identities solver free
    cos^2x-cot^2x=cos^2xcot^2x

    (1-cosx)/(1+cosx)=(cotx-cscx)^2

    1/tanx-secx+1/tanx+secx=-2tanx

    sec^4x-sec^2x=tan^4x+tan^4x

    cosx/1-sinx=1+sinx/cosx

    1-secxcosx=tanxcotx-1

    sinx+cosx=secx+cscx/cscx+secx

    sinx=sin^3+cos^2xsinx

    sinx+cosx+1=2sinxcosx/sinx+cosx-1
  • Feb 18, 2013, 08:13 AM
    ebaines
    In almost all cases the way to approach these problems is to first convert tangent, cotangent, secant, and cosecant function to their sine and cosine equivalents, and then simplify the expression. You also may have to apply a few key identites that you must be familiar with, such as:

    sin^2x +cos^2x = 1
    sin2x = 2sinx cosx
    cos2x = cos^2x - sin^2x = 2 cos^2x - 1 = 1 - 2 sin^2x

    Memorize these and look for opportunities to apply them.
  • Apr 5, 2013, 01:56 PM
    MDAncell
    Verify
    csc(x)cos^(2)(x)+sin(x)=csc(x)
  • Apr 5, 2013, 02:34 PM
    ebaines
    Quote:

    Originally Posted by MDAncell View Post
    Verify
    csc(x)cos^(2)(x)+sin(x)=csc(x)

    See the advice given earlier in post #2 - it works well on this problem.
  • Apr 7, 2013, 01:25 PM
    elisa2520
    verify each

    (sin 2x) (sec x) (csc x)=2

    (sin 2x)^2=4 (1-sin^2 x-cos^4x)

    prove:

    sin 2x cosx=2 (sinx-sin3x)
  • Apr 8, 2013, 05:57 AM
    ebaines
    elisa2520: each of these can be solved if you apply the identity for sin(2x) - you should memorize this:



    You will also have to apply the fundamental identity and its variations (e.g. ).

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