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ln K = -5.569 please solve this question for me!
Can someone explain to be the concepts and procedure to solving something like the following question? (I) log4 2 ! Log9 (2x ! 5) # log8 64
So, here's another question that I am having trouble with: - log(5)y = 2 I followed the steps that were used in a sample question just like this one and I still got the wrong answer... or I just don't know how to finish it. Here's what I've done: (2/log(5)3) * log(5)x = 2 + log(5)y ...
Here is the question I have to answer: 5log(2)y – log(2)x = 3log(2)4 + log(2)a (I'm sorry if this is not written properly. I'm not sure how to do subscript typing for the 2s.) This is what I've come up with: log(2)y^{5} = 3log(2)2^{2} + log(2)a + log(2)x log(2)y^{5} = 3log(2)2^{2} +...
got stuck on this one... use the properties of logarithms to rewrite the expression in terms of log(base 10)of 3 and log(base 10) of 4. Then use log(base10) of 3 = 0.477 and log (base 10) of 4 =0.602 to approximate the expression. then these are the two I have to solve. a. log (base 10) of 16...
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