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    brynscalltoarms's Avatar
    brynscalltoarms Posts: 7, Reputation: 1
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    #1

    May 14, 2012, 02:49 PM
    Steps to proving the trig identity
    (1+csc^2x) / (1+cscx) = (1+sinx) / sinx

    I already attempted doing this and I basically got the right answer, except I got

    sinx+1 / sinx instead of 1+sinx/sinx
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    May 15, 2012, 06:30 AM
    Quote Originally Posted by brynscalltoarms View Post
    (1+csc^2x) / (1+cscx) = (1+sinx) / sinx

    I already attempted doing this and I basically got the right answer, except I got

    sinx+1 / sinx instead of 1+sinx/sinx
    There seems to be a typo in your question - the expression:



    equals neither nor

    Please check the expression the equation that you're working on..
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