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    bribrianna's Avatar
    bribrianna Posts: 1, Reputation: 1
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    #1

    Jan 5, 2012, 02:49 PM
    Algebra II substitution problems?
    This is Algebra II substitution... how do you solve it? And please no just the answer show your work please :(

    1)2x+y=8 x-y=10 And I was also wondering if you mark it consistent,
    independent or are there anything else your can
    "label" the as?

    2)3x+4y=23 -3x+y=2
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Jan 5, 2012, 03:06 PM
    Starting with:

    2x+y = 8
    x-y = 10

    From the second equation you can see that x = 10+y. So replace the 'x' in the first equation with '10+y', and you get:

    2(10+y)+y = 8

    Now you can simplify and solve for y. Then put that value for y back into the second equation and solve for x.

    Alternatively, if you simply add these two equations together the 'y' terms cancel out:

    (2x + y) +(x - y) = 8 + 10, or:
    3x = 18

    Now you can solve for 'x,' then put that value back into of the original two equations and solve for 'y'.

    The second problem can be solve in a similar way. Post back with your answers and we'll check them for you.
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