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    jananewbould's Avatar
    jananewbould Posts: 1, Reputation: 1
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    #1

    Jun 26, 2008, 11:40 AM
    Substitution for Algebra
    So I have this problem:

    x + 2y + z = 0
    -3x + 3y + 2z= -7
    4x - 2y - 3z= 2

    Does anyone know the steps I should use to solve this using substitution?
    HELP!

    Thanks
    Jana
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Jun 26, 2008, 11:46 AM
    Usually the best place to start is to look at the equations and decide which would be easiest to rearrange to get either the x, y, or z by itself on one side. In this case the first equation looks simplest, since neither the x nor z term have coefficient and the right hand side is zero. So pick either the x or z and get it all alone on one side of the equation. For example, you can rearrange it to get:
    x = 0-2y-z = -2y +z.
    Now sub for that in the other two equations:

    -3(-2y-z) + 3y +2z = -7
    4(-2y-z) -2y - 3z = 2

    You now have 2 equations in 2 unknowns. Can you take it from here?
    nuclear_sugar's Avatar
    nuclear_sugar Posts: 13, Reputation: 1
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    #3

    Jun 26, 2008, 11:53 AM
    I remember when I learned it... but I can't remember much about the solution, except that you have to "add the equations" together, like putting them as you had written them above, then adding each variable together... but I think you somehow have to do it as many times as you have variables, and for that, I CANNOT remember how! I even made straight A's in it, but it's been a decade since I've used it. Sorry! Good luck!
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Jun 27, 2008, 03:29 AM
    That method I think is called elimination method, whereby you get rid of some variables, leaving those you can deal with more easily
    Mckenzie1046's Avatar
    Mckenzie1046 Posts: 1, Reputation: 1
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    #5

    Jan 5, 2009, 05:00 PM
    Comment on ebaines's post
    The question was concerning how to use elimination in solving the equation. The answer given was how to solve the equation by substitution and therefore not helpful.

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