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    sekoni's Avatar
    sekoni Posts: 1, Reputation: 1
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    #1

    Nov 17, 2011, 11:40 AM
    Bearing and distance
    If r and s are on the same horizontal ground as the foot p of a tower pq.if the tower is 18km due north of s and 24km east of r if the bearing of q from s is 035 degree find the height pq of the tower and distance of r and s
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Nov 17, 2011, 12:06 PM
    Make a sketch and use your trigonometric ratios to get the answer.

    Using the angle of depression (not sure why you call it bearing, or the question gives it as bearing... ) and the distance of p to s gives you the height of pq.

    Using Pythagoras' Theorem, you get the distance rs.

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