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    tkd510 Posts: 1, Reputation: 1
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    #1

    Nov 3, 2011, 07:55 PM
    Statistics homework question on probability, please help.
    A basketball player hits three-point shots 41% of the time. If she takes 4 shots during a game, what is the probability that she misses the first shot and hits the last three shots.
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    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Nov 4, 2011, 02:12 AM
    P(miss 1st, hits 2nd, hits 3rd, hits 4th) = P(miss first) x P(hits 2nd) x P(hits 3rd) x P(hits 4th)

    Can you work out each of them?
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